How To Create Spanish Crossword Puzzles

by on in Guides

Crosswords are fun and intellectually challenging, but they can also fulfill educational and knowledge-based requirements. We believe that the language you speak should not be a barrier to your online crossword experience.

That’s why we’re thrilled to announce that you can now use PuzzleMe create online Spanish crosswords! PuzzleMe, powered by Amuse Labs, lets users easily create crossword puzzles in French and 36 other languages!

Create Spanish Crossword

Create Spanish Crosswords With PuzzleMe

You can create a crossword puzzle on PuzzleMe via four channels, i.e., Crossword Copilot, List Entries, Empty Grid and Magic Fill. These methods vary in terms of difficulty levels and grid placement control, and once created, they are easily editable.

This blog focuses on creating crosswords using the list entries method, which is the most straightforward manual method to create spanish crosswords on PuzzleMe. 

Getting Started:

  1. Go to the PuzzleMe creator.
  2. From your new game dashboard, select “Crossword”.

List Entries:

  1. Enter your crossword’s title.
  2. Choose “Spanish (Spain)” from the game language option.
  3. The default method for creating crosswords is the list entries method.
  4. If you want to customise the grid size, go to “Fixed grid size” and select your grid size preference.
  5. Then go to the “crossword entries” and list the word entries you want to place on the crossword grid one by one.
  6. Texts and images can also be used to specify the clues to these entries.
  7. To avoid losing progress, log in or sign up and link your account. It also allows you to save the game and share its playable version with others.
Create Spanish Crossword

Spanish Crosswords Created On PuzzleMe

Spanish Crossword

PuzzleMe powers daily Spanish crosswords for ABC, a national daily in Spain. ABC, the biggest newspaper in the capital Madrid, offers its viewers the option of solving four types (mini, easy, medium, and hard) of crossword puzzles based on their preferred difficulty level.

Aditya Anurag Roy
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